To find:(a)radiative force R when the carbon dioxide level is double the preindustrial amount of carbon dioxide in watts per square meter by using {R}={6.3}frac{ ln{{C}}}{{C}_{{0}}} (b)the global temperature increase T by using T(R)=1.03R

Kaycee Roche

Kaycee Roche

Answered question

2021-01-10

To find:(a)radiative force R when the carbon dioxide level is double the preindustrial amount of carbon dioxide in watts per square meter by using\ R=6.3lnCC0
(b)the global temperature increase T by using T(R)=1.03R

Answer & Explanation

davonliefI

davonliefI

Skilled2021-01-11Added 79 answers

Concept:
Modeling is a method of simulating the real life situations with mathematical equations. Using these models we can forecast the future behavior. We can translate the mathematical word problem into a math expression using variables.
Calculation:
The given model is R=klnCC0, R is the radiative forcing in watts per square meter. Where ( is the preindustrial amount of carbon dioxide,
C is the current level of carbon dioxide.
And, according to IPCC, k = 6.3
(a) Let R=6.3lnCC0
And given that, the carbon dioxide level = double the preindustrial amount of carbon dioxide
That is, C=2C0
So, let C=2C0
R=63In2C0C0
Cancel C0,R=6.3ln2C0C0
R=63ln2
Using calculator, R=6.3×0.6931
R = 4.3668
R4.37 watts per square meter.
Hence, radiative force R when the carbon dioxide level is double the preindustrial amount of carbon dioxide is 4.37 watts per square meter.
(b) Let R = 4.37 watts per square meter
And the global temperature increase T(R) = 1.03R
So, when R=4.37,T(R)=1.03×4.37
Therefore, T(R) = 4.50
Final statement:
Based on the given function,
(a) radiative force R when the carbon dioxide level is double the preindustrial amount of carbon dioxide is 4.37 watts per square meter.
(b) the global temperature increase T = 4.50

Do you have a similar question?

Recalculate according to your conditions!

New Questions in Math Word Problem

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?