The reduced row echelon form of the augmented matrix of a system of linear equations...
Burhan Hopper
Answered question
2021-06-23
The reduced row echelon form of the augmented matrix of a system of linear equations is given. Tell whether the system has one solution, no solution, or infinitely many solutions. Write the solutions or, if there is no solution, say the system is inconsistent.
Answer & Explanation
Latisha Oneil
Skilled2021-06-24Added 100 answers
There are two columns before the vertical bar, so there are two variables.
Each variable is represented by a leading 1, so there are no parameters needed.
There are no impossible equations , such as (0=1).
The system is consistent and has exactly one solution.
(No parameters) Interpreting row by row as equations.
Each variable is represented by a leading 1, so there are no parameters needed.
There are no impossible equations , such as (0=1).
The system is consistent and has exactly one solution.
(No parameters) Interpreting row by row as equations.
