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2023-02-18

Yellow light emitted from a sodium lamp has a wavelength ($\lambda$) of 580 nm. Calculate the frequency (ν) and wave number ($\overline{V}$) of the yellow light.

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From the wording,
$\lambda =\frac{c}{v}$
we get,$v=\frac{c}{\lambda }$.............(i)
Where, ν = frequency of yellow light
c = velocity of light in vacuum
$\lambda$ = wavelength of yellow light Substituting the values in expression (i):
$v=\frac{3×{10}^{8}}{580×{10}^{-9}}=5.17×{10}^{14}{s}^{-1}$
As a result, the sodium lamp's yellow light emission frequency $=5.17×{10}^{14}{s}^{–1}$
Wave number of yellow light $\overline{v}=\frac{1}{\lambda },\phantom{\rule{0ex}{0ex}}=\frac{1}{580×{10}^{-9}}=1.72×{10}^{6}{m}^{-1}$

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