A concave mirror has a focal length of 4 cm and an object 2 cm...

Focal length = f = - 4 cm
Height of object = + 2 cm
Object distance = u = - 9 cm
Image distance = v = ?
Height of image = size = h' = ?
From thew mirror formula
$\frac{1}{v}+\frac{1}{u}=\frac{1}{f}$

Putting all the values
$\frac{1}{v}-\frac{1}{9}=\frac{1}{-4}$

After solving
v=−7.2cm

As a result, the image is created 7.2 cm away from the mirror.

Now for finding magnification
We know,
$m=\frac{-v}{u}$

Putting all the values
$\frac{-(-7.2)}{-9}$

After solving
m=−0.8


As the magnification is negative, the image is real, inverted.