Skilled2020-10-21Added 119 answers
The key in this situation is to adjust the variables. In particular, if you encounter a square root, you should either set it to something squared under the square root or convert it to something else whichever is beneath it. We'll choose the latter in this instance.
Let .Then, because we know , we see that which is equivalent to . We obtain by substituting these into the integral.
This is a portion of what we want, but there is still a xx in there, and we like to completely switch to uu's. I mean, keep in mind that we set . Let's solve that for x in terms of u:
By replacing this, we obtain