Do either of the linear transformation properties imply the other? I'm new to linear algebra and

Krystal Villanueva

Krystal Villanueva

Answered question

2022-02-13

Do either of the linear transformation properties imply the other?
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Answer & Explanation

Amiya Wolf

Amiya Wolf

Beginner2022-02-14Added 11 answers

Consider two vector spaces V, V' and a map T:VV. If for any v1,v2V,T(v1+v2)=Tv1+Tv2, then nZ,T(nv1)=Tv1++Tv1=nTv1, and hence αQ,vV,T(αv)=αTv.
Given any irrational number 0<r<1, we can write r=k=110krk. That is, ϵ>0,NN such that every positive integer nN gives 0<rk=1n10krk<ϵ. In this case, vV,rTv>T(k=1n10krkv)=Tvk=1n10krk>(rϵ)Tv.
This implies T(rv)=rT(v)rR.
For the other direction, v1,v2V,T(v1+v2)=T(v1(1+v2v1)), provided v1,v2=(1+v2v1)Tv1=Tv1+Tv2
are scalar multiples of each other or V is 1 dimensional.
Note that given T(1,0,0) and T(0,0,1), it is impossible to find T(1,0,1) as (1,0,1) is not a scalar multiple of either (1,0,0) or (0,0,1).

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