If the tangent line to y = f(x) at (4, 3) passes through the point...

The tangent to y=f(x) at (4,3)
This suggest that ${\displaystyle (4,3)}$ is a point on the graph of y=f(x)
Therefore, ${\displaystyle f\left(4\right)=3}$
Slope of the tangent at x=4 to y=f(x) is f'(4)
Since the tangent passes through (4,3) and (2,0), its slope is equal to
${\displaystyle m=\frac{2-3}{0-4}=\frac{-1}{4}=0.25}$
This is equal to f'(4)
Result: f(4)=3 and f'(4)=0.25