Evaluate the integral. ∫027x−2dx

Ava-May Nelson

Ava-May Nelson

Answered question

2021-10-28

Evaluate the integral.
027x2dx

Answer & Explanation

Obiajulu

Obiajulu

Skilled2021-10-29Added 98 answers

Step 1
Given definite integral is:
027x2dx
We have to determine whether the above integral converges or diverges.
Step 2
Then we get,
027x2dx
=7[ln|x2|]02
=7(ln|22|ln|02|)
=7(ln0ln|2|)
=7ln0
Since ln0 is undefined therefore the given integral cannot converge and hence is divergent.

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