Evaluate the integrals \int_{\sqrt{3}}^3\frac{dt}{3+t^2}

Dillard

Dillard

Answered question

2021-10-20

Evaluate the integrals
33dt3+t2

Answer & Explanation

Alannej

Alannej

Skilled2021-10-21Added 104 answers

We have to evaluate the integral
33dt3+t2
We know
dxx2+a2=1atan1(xa)
Therefore,
dxx2+a2=1atan1(xa)
Therefore,
33=33dtt2+(3)2
=[13tan1(t3]33
=[13π313tan1(1)]
=[13(π3π4]
=13π12
=π123
=3π36

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?