Skilled2020-12-02Added 95 answers
Consecutive integers differ by 1 so we let the four consecutive integers be:
The sum of the squares of the first two is 11 less than the square of the fourth so:
Solve for x:
Factor the left side: (x−1)(x−3)=0
By zero product property, x=1,3
There are two possible sets of consecutive integers: 1,2,3,4 or 3,4,5,6
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