How to evaluate int sqrt(x^2+14x)dx?

kennisnetto1h

kennisnetto1h

Answered question

2023-02-18

How to evaluate x 2 + 14 x d x?

Answer & Explanation

affwysaumlgx

affwysaumlgx

Beginner2023-02-19Added 12 answers

We need
cosh 2 θ - sinh 2 θ = 1
cosh 2 θ = 2 sinh 2 θ + 1
sinh 2 θ = 1 2 ( cosh 2 θ - 1 )
sinh 2 θ = 2 sinh θ cosh θ
a r c cosh x = ln ( x 2 - 1 + x )
By substituting, we perform this integral, but first we simplify.
x 2 + 14 x = x 2 + 14 x + 49 - 49 = ( x + 7 ) 2 - 49
The substitution is
x + 7 = 7 cosh θ
d x = 7 sinh θ d θ
( x + 7 ) 2 - 49 = 49 cosh 2 θ - 49
= 7 cosh 2 θ - 1
= 7 sinh θ
sinh 2 θ = cosh 2 θ - 1 = ( x + 7 7 ) 2 - 1
= x 2 + 14 x + 49 - 49 49
= x 2 + 14 x 49
sinh θ = 1 7 x 2 + 14 x
Then, x 2 + 14 x d x = 7 sinh θ 7 sinh θ d θ
= 49 sinh 2 θ d θ
= 49 2 ( cosh 2 θ - 1 ) d θ
= 49 2 ( sinh 2 θ 2 - θ )
= 49 2 ( sinh θ cosh θ - a r c cosh ( x + 7 7 ) )
= ( 49 2 1 7 x 2 + 14 x x + 7 7 ) - 49 2 ( ln ( ( x + 7 ) 2 49 - 1 ) + x + 7 7 ) + C
= 1 2 ( x + 7 ) x 2 + 14 x - 49 2 ln ( | 1 7 ( x 2 + 14 x + ( x + 7 ) ) | ) + C

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