How to reduce equation? p = e β 0 + β 1 ∗ a g e e β 0 + β 1 ∗ a g e + 1 to log e ⁡ p 1 − p = β 0 + β 1 ∗ a g e

Question

How to reduce equation?  p  =            e                        β          0                +                  β          1                ∗        a        g        e                            e                              β            0                    +                      β            1                    ∗          a          g          e                    +      1      to       log    e    ⁡      p          1      −      p        =      β    0    +      β    1    ∗  a  g  e

Theresa Wade · Accepted Answer

Let   K  =      e                  β        0            +              β        1            ×      a      g      e      . Then  p  =      K          K      +      1        ⇝  p  K  +  p  =  K  ⇝  p  =  K  −  K  p  ⇝      p          1      −      p        =  KFinally take       log    e   on both sides.

link223mh · Accepted Answer

p  =      k          k      +      1        ⇒  k  p  +  p  =  k  ⇒  k  =      p          1      −      p      here   k  =      e                  β        0            +              β        1            a      g      e      . Take   ln on both sides.

How to reduce equation? p = \frac{e^{\beta_0 + \beta_1 * age}}{e^{\beta_0 + \beta_1 * age} + 1} to \log_e \frac{p}{1-p} = \beta_0 + \beta_1*age

Answered question

Answer & Explanation

New Questions in Inferential Statistics