How to count n th percentile from normally distributed random variable? I have normally distr

Jackson Duncan

Jackson Duncan

Answered question

2022-06-26

How to count nth percentile from normally distributed random variable?
I have normally distributed random variable X N ( 100 , 225 ). How to count nth percentile?
In my case I need lower quartile - x ( 0.25 )

Answer & Explanation

upornompe

upornompe

Beginner2022-06-27Added 20 answers

In general, if X N ( μ , σ 2 ), then
X μ σ N ( 0 , 1 )
follows a standard normal distribution. If F X denotes the cumulative distribution function of X and Φ is that of a standard normal distribution, then
F X ( x ) = P ( X x ) = Φ ( x μ σ ) .
Let us find the pth quantile/percentile of X, where p ( 0 , 1 ), in terms of the pth quantile/percentile of a standard normal distribution. Let y denote the pth quantile of a standard normal distribution, i.e.
Φ ( y p ) = p .
If we let x p = σ y p + μ then
F X ( x p ) = Φ ( x p μ σ ) = Φ ( y p ) = p ,
i.e. x p is the pth percent of X
So all you need to know is the pth quantile of the standard normal distribution which can be found in tables, and then you can find pth quantiles for every normal distribution.
Note that some tables only index probabilities p 0.5, because the rest can be deduced from these quantiles by symmetry. Recall that 1 Φ ( x ) = Φ ( x ) for all x. If q < 0.5 and p = 1 q, then p 0.5 and we can look up the pth quantile x p . By symmetry:
q = 1 p = 1 Φ ( x p ) = Φ ( x p )
and so x q = x p , i.e. the qth quantile is minus the pth quantile.

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