Arithmetic sequence is given by a5=0 and a15=4What

Haseeb Ahmed

Haseeb Ahmed

Answered question

2022-06-02

Arithmetic sequence is given by a5=0 and a15=4

What is the sum of the first 15 terms of that arithmetic sequence

Answer & Explanation

karton

karton

Expert2022-08-01Added 613 answers

nth term of an Arithmetic Sequence is given by,

an=a+(n-1)d

where

a denotes the first term

d denotes the common difference

 

5th term = 0

a + (5 – 1)d = 0

a + 4d = 0

a = –4d

 

15th term = 4

a + (15 – 1)d = 4

a + 14d = 4

 

Put a = –4d,

–4d + 14d = 4

10d = 4

d = 4/10

d = 0.4

Common differences = 0.4

 

first term, a = –4(0.4) = –1.6

 

Sum of first n terms of Arithmetic sequence is given by,

Sn=n2[2a+(n-1)d]

The sum of first 15 terms of the given Arithmetic sequence is

= 15/2 [2(-1.6) + (15–1)(0.4)]

= 7.5 [–3.2 + 14(0.4)]

= 7.5 [–3.2 + 5.6]

= 7.5 [2.4]

= 18

Therefore, the required sum of first 15 terms is 18

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