A card is drawn and replaced five times from an ordinary deck of 52 cards and the sequence of colors is observed. What is the probability that: a) Five red cards were drawn? b) five black cards were drawn? c) Three red and two black cards were drawn? d) why is it necessary to replace the cards?

odcizit49o

odcizit49o

Answered question

2022-11-15

A card is drawn and replaced five times from an ordinary deck of 52 cards and the sequence of colors is observed. What is the probability that:
a) Five red cards were drawn?
b) Five black cards were drawn?
c) Three red and two black cards were drawn?
d) why is it necessary to replace the cards?
My thoughts:
a) 5 P 1 ( 26 52 ) 1 ( 1 p ) 4 + . . . + 5 P 5 ( 26 52 ) 5 ( 1 p ) 0
b) isn't this the same as part (a) ?
c) isn't this the same as asking exactly 5 black or red cards were drawn ?
d) not sure about this one.

Answer & Explanation

Lillianna Salazar

Lillianna Salazar

Beginner2022-11-16Added 22 answers

Step 1
a) Each time you have 1 2 chance of a given color. b) yes, this is the same as a c) no, because there are many combinations of three red and two blacks.
Step 2
Each specific order is the same as a or b d) it is not necessary to replace the cards, but the probabilities will change. If you are looking for five reds, after you draw the first red the chance of the second is 25 51 and so on.
Jaslyn Sloan

Jaslyn Sloan

Beginner2022-11-17Added 6 answers

Step 1
The probability of picking a type of card is
# of cards of that type left in the deck total # of cards in the deck before drawing
Step 2
c) Doesn't tell you in what order they were drawn: how many different orders are there?
d) Looking at the fraction/ratio above, what happens to the numerator and denominator if you don't replace a card before drawing?

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