If A and B are mutually exclusive events, and P(B)>0 , show that P(A|A∪B)=(P(A))/(P(A)+P(B))

Nasir Sullivan

Nasir Sullivan

Answered question

2022-09-24

If A   and   B are mutually exclusive events, and P ( B ) > 0, show that
P ( A | A B ) = P ( A ) P ( A ) + P ( B )
My try:
1. We know that if A   and   B are mutually exclusive events, then P ( A B ) = P ( A ) + P ( B )
2. We know that P ( A | B ) = P ( A B ) P ( B )

Answer & Explanation

Guadalupe Reid

Guadalupe Reid

Beginner2022-09-25Added 8 answers

regardless that A   and   B are joint or disjoint,
A ( A B ) = A
you can verify it simply with a Venn's Diagram. This is also self evident observing that
A ( A B )

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