The next three batters on a baseball team have hit percentages of 0.325, 0.250, and 0.275, respectively. What is the probability that the first and third batters will both get a hit, while the second batter does not?

maredilunavy

maredilunavy

Answered question

2022-09-15

The next three batters on a baseball team have hit percentages of 0.325, 0.250, and 0.275, respectively. What is the probability that the first and third batters will both get a hit, while the second batter does not?

Answer & Explanation

Edward Chase

Edward Chase

Beginner2022-09-16Added 10 answers

The probability that a batter will get a hit is equal to his batting percentage (I'll use B for "Batter"):
B 1 = .325
B 2 = .250
B 3 = .275
and so the probability of a batter to not get a hit is simply 1 − batting percentage (we can use the ! sign to indicate "not"):
! B 1 = 1 - .325 = .675
! B 2 = 1 - .250 = .750
! B 3 = 1 - .275 = .725
The probability of B 1 is .325
The probability of B 2 is .750
The probability of B 3 is .275
We can multiply these (since they are independent events and so we use the Counting Principle) to get the probability of all three happening:
.325 × .750 × .275 .067 = 6.7 %

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