If you have k trials that result in 5,6,7 with probabilities P(5), P(6), and P(7) (respectively), with P(5)+P(6)+P(7)=1, what is the probability that 5 and 6 occur at least once.

Gauge Odom

Gauge Odom

Answered question

2022-09-07

If you have k trials that result in 5,6,7 with probabilities P(5), P(6), and P(7) (respectively), with
P ( 5 ) + P ( 6 ) + P ( 7 ) = 1,
what is the probability that 5 and 6 occur at least once.
Would it be 1 P ( 5 and 6 never occur ) = 1 ( P ( 5 ) + P ( 6 ) ) 0 ( P ( 7 ) ) n = 1 P ( 7 ) n

Answer & Explanation

Aleah Harrell

Aleah Harrell

Beginner2022-09-08Added 18 answers

Step 1
I assume k andn are the same. 1 p 7 k is the chance of at least one trial not being 7, so at least one 5 or one 6.
Step 2
Is that what you wanted, or the probability of at least one 5 and at least one 6?
tamola7f

tamola7f

Beginner2022-09-09Added 2 answers

Step 1
I think you mean the probability that there is at least one 5 and at least one 6 in k independent trials. Let A 5 be the event that there is at least one 5, A 6 the event that there is at least one 6.
Step 2
The probability that there is at least one 5 or at least one 6 is P ( A 5 A 6 ) = 1 p 7 k , while P ( A 5 ) = 1 ( p 6 + p 7 ) k and P ( A 6 ) = 1 ( p 5 + p 7 ) k .

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