Events A,B,C are such that B and C are mutually exclusive and P(A)=2/3,P(A∪B)=5/6 and P(B∪C)=4/5. If P(B|A)=1/2 and P(C|A)=3/10, calculate P(C).

cottencintu

cottencintu

Answered question

2022-08-11

Events A , B , C are such that B and C are mutually exclusive and P ( A ) = 2 / 3 , P ( A B ) = 5 / 6 and P ( B C ) = 4 / 5. If P ( B | A ) = 1 / 2 and P ( C | A ) = 3 / 10, calculate P ( C ).

Answer & Explanation

Nicole Soto

Nicole Soto

Beginner2022-08-12Added 10 answers

You correctly guessed that we need P ( B ) first. Since P ( A ) is known, we should look for relations between A , B.
They are P ( A B ) = 5 / 6 , P ( B | A ) = 1 / 2.
By definition P ( B | A ) = P ( A B ) / P ( A ) which gives P ( A B ) = 1 2 × P ( A ) = 1 / 3.
We know P ( A B ) = P ( A ) + P ( B ) P ( A B ) = 5 / 6 using which find P ( B ).
Finally P ( B C ) = P ( B ) + P ( C ) since P ( B C ) = 0 ,, using which find P ( C ).

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