Averi Mitchell

2022-06-20

I believe this question involves the rule of sum and the fundamental counting principle. I think my logic here is wrong, but I hope you could correct it.
(26 P 2 + 26 P 3)(10 P 4) = 8.19*10^7

Samantha Reid

If the letters and digits cannot be repeated, then your answer is correct.
If they can, then you have 26 options every time you select a letter, and 10 options every time you select a digit, so it would be $\left({26}^{2}+{26}^{3}\right)\cdot {10}^{4}$

Do you have a similar question?