I'm sorry for the basic question, but I can't figure this out. Suppose you want to find how many ev

rose2904ks

rose2904ks

Answered question

2022-06-14

I'm sorry for the basic question, but I can't figure this out.
Suppose you want to find how many even, non-repeating 3-digit numbers there are. If you choose the last digit to be non-zero, you have ( 8 ) ( 8 ) ( 5 ) = 320 possibilities. If you choose the last digit to be zero, you have ( 9 ) ( 8 ) ( 5 ) = 360 possibilities. What should I do?

Answer & Explanation

ejigaboo8y

ejigaboo8y

Beginner2022-06-15Added 29 answers

If you choose the last digit to be non-zero ( { 2 , 4 , 6 , 8 }), we have
( 8 ) ( 8 ) ( 4 )
If you choose the last digit to be zero { 0 }, we have
( 9 ) ( 8 ) ( 1 )
then sum them up.

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