Simplify, please: \frac{n!}{(n-3)!}

Alfred Martin

Alfred Martin

Answered question

2021-12-20

Simplify, please:
n!(n3)!

Answer & Explanation

Jim Hunt

Jim Hunt

Beginner2021-12-21Added 45 answers

n!(n3)!
=n(n1)(n2)(n3)(n4).×3×2×1(n3)(n4)×3×2×1
=n(n1)(n2)
n(n23n+2)
=n23n2+2n
Paineow

Paineow

Beginner2021-12-22Added 30 answers

n!(n3)!
Cancel the factorials: n!(nm)!=n×(n1)(nm+1), n>m
Thus, we have
n!(n3)!=n(n1)(n2)
RizerMix

RizerMix

Expert2021-12-29Added 656 answers

n!(n3)!=n(n1)(n2)=n23n2+2n

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