Find the following probabilities for the standard normal variable z:(a) P(-1.96<=z<=1.96)(b)P(z>1.96)(c)P(z<-1.96)

Elleanor Mckenzie

Elleanor Mckenzie

Answered question

2021-08-21

Find the following probabilities for the standard normal variable z:
(a) P(1.96z1.96)
(b) P(z>1.96)

(c) P(z<1.96)

Answer & Explanation

Jayden-James Duffy

Jayden-James Duffy

Skilled2021-08-22Added 91 answers

(a)
P(1.96z1.96)
Determine the corresponding probability using the normal probability table in the appendix.
P(z<1.96)is given in the row starting with 1.9 and in the column starting with 0.06 of the standard normal probability table in the appendix.
P(z<1.96)=0.9750
P(z<1.96) is given in the row starting with -1.9 and in the column starting with 0.06 of the standard normal probability P(z<1.96)=0.0250
The probability between two boundaries is the difference between the probabilities to the left of both boundaries.
P(1.96) (b)
P(z>1.96)
Determine the corresponding probability using the normal probability table in the appendix. P(z>1.96) is given in the row starting with 1.9 and in the column starting with 0.06 of the standard normal probability table in the appendix.
P(z>1.96)=0.9750
Use the Complement rule: P(Ac)=P(¬A)=1P(A)
P(z>1.96)=1P(z<1.96)=10.9750=0.0250
(c)
P(z<1.96)
Determine the corresponding probability using the normal probability table in the appendix.
P(z>1.96) is given in the row starting with 1.9 and in the column starting with 0.06 of the standard normal probability table in the appendix.
P(z<1.96)=0.0250
Result:(a)0.9500.(b)0.0250.(c)0.0250.

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