The region between the graphs of y=x^{2} and y=3x is rotated ariund the line x=3.

Rigoberto Drake

Rigoberto Drake

Answered question

2022-11-12

Finding Volume of the Solid-washer method
The region between the graphs of y = x 2 and y = 3 x is rotated around the line x = 3.
What is the volume of the resulting solid?
I drew the picture, and I saw that I should be using the washer method. Since the region was being flipped at x = 3, I would have to make sure I am subtracting the two functions from 3 and then subtract those two, but I could not seem to get the right answer.

Answer & Explanation

erlentzed

erlentzed

Beginner2022-11-13Added 22 answers

Step 1
Using washers, the interval of integration will be along the y-axis from y = 0 to y = 9. The inner radius as a function of the y-value will be r ( y ) = 3 y , and the outer radius will be R ( y ) = 3 y / 3; thus the differential volume of a washer with thickness dy is
d V = π ( R ( y ) 2 r ( y ) 2 ) d y = π ( ( 3 y / 3 ) 2 ( 3 y ) 2 ) d y ,
and the total volume is given by the integral
V = π y = 0 9 ( 3 y / 3 ) 2 ( 3 y ) 2 d y .
Step 2
Using cylindrical shells, the interval of integration will be along the x-axis from x = 0 to x = 3. The height of the shell is given by the difference of the functions y = x 2 and y = 3 x, so h ( x ) = 3 x x 2 (since 3 x x 2 on x [ 0 , 3 ]). The circumference of a representative shell is simply 2 π ( 3 x ), thus its differential volume is
d V = 2 π ( 3 x ) ( 3 x x 2 ) d x ,
and the total volume is
V = x = 0 3 2 π ( 3 x ) ( 3 x x 2 ) d x .
Both calculations give the same result.
ajakanvao

ajakanvao

Beginner2022-11-14Added 4 answers

Explanation:
Volume by washers can be used in this case if you stack your washers parallel to the x-axis, centered at x = 3. Identify the outer radius R (as a function of y, since every washer is determined by how high it's sitting in the stack) and the inner radius (again, as a function of y); the volume of each thin washer is π ( R 2 r 2 ) Δ y and the total volume is π 0 9 ( R 2 r 2 ) d y.

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