Probability of finding n_{1} particles in volume v_{1} and n_{2} particles in volume v_{2}.

Amira Serrano

Amira Serrano

Answered question

2022-11-01

Probability of finding n 1 particles in volume v 1 and n 2 particles in volume v 2 .
The formula is:
P [ n  particles in  V ] = ( N n ) p n ( 1 p ) N n where p is p = v V .
I would like to know how this formula generalizes if one wants to compute "the probability of finding n 1 particles in volume v 1 and n 2 particles in volume v 2 , given that there are N indistinguishable particles in total, that the total volume is V and that v 1 and v 2 are disjoint."

Answer & Explanation

encaselatqr

encaselatqr

Beginner2022-11-02Added 11 answers

Step 1
If you consider p 1 = v 1 / V and p 2 = v 2 / V then P [ n 1   particles in   v 1   and   n 2   particles in   v 2 ] = N ! n 1 ! n 2 ! ( N n 1 n 2 ) ! p 1 n 1 p 2 n 2 ( 1 p 1 p 2 ) N n 1 n 2
Step 2
That's because if you choose n 1 particles, the probability they all fall into v 1 is p 1 n 1 , then, if you choose n 2 other particles, the probability they all fall into v 2 is p 2 n 2 and the probability the remaining N n 1 n 2 particles doesn't fall into v 1 or v 2 is ( 1 p 1 p 2 ) N n 1 n 2 . Finally, there are N ! n 1 ! n 2 ! ( N n 1 n 2 ) ! ways of choosing the particles that way as explained in (1.24) in the lecture notes you linked.
This is called a multinomial distribution and it can be generalized to k disjoint volumes.

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