Let X,Y∼G(p) be independent Geometric random variables (p in (0,1)). Show that P(X=Y)=p/(2-p).

Garrett Sheppard

Garrett Sheppard

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2022-08-16

Joint Probability of Independent Geometric Random Variables
Let X , Y G ( p ) be independent Geometric random variables ( p ( 0 , 1 )). Show that P ( X = Y ) = p / ( 2 p ).

Answer & Explanation

Jakob Chavez

Jakob Chavez

Beginner2022-08-17Added 14 answers

Step 1
Sometimes "geometric distribution" means a distribution supported on {0,1,2,3,…} and sometimes it means a distribution supported on {1,2,3,…}. Assuming the latter, you have Pr ( X = Y ) = Pr ( X = Y = 1 ) + Pr ( X = Y = 2 ) + Pr ( X = Y = 3 ) + Pr ( X = Y = 4 ) + = p 2 + p 2 ( 1 p ) 2 + p 2 ( 1 p ) 4 + p 2 ( 1 p ) 6 + . .
Step 2
Remember that a + a r + a r 2 + a r 3 + = a 1 r .
In this case a = p 2 and r = ( 1 p ) 2 .
So the sum comes to p 2 p .
In the case of the support being {0,1,2,3,…} you'd start the sum with Pr ( X = Y = 0 ), but the rest is the same.

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