nidantasnu

2022-07-02

Find the equation of angle bisector passing through quadrant containing (2,3).
${L}_{1}⇒2x+y-1=0$
${L}_{2}⇒2x-y+3=0$

Savion Stanton

Expert

Step 1
$y=1-2x,y=2x+3$ . Point of intersection is $\left(-\frac{1}{2},2\right)$ . Note that the slopes are opposite so one bisector is vertical and one is horizontal. The required bisector is $y=2$