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Analytic geometry
Jason Watson
2021-11-28
Melinda Olson
Beginner2021-11-29Added 20 answers
Given figurc We find thc volue of t From thc figure we sec thc t ∠AOB+∠BOC=180° [∴∠AOBand∠BOC are lincar pair] ⇒41°+t=180° [∴∠AOB=41°∠BOC=t] ⇒t=180°−41° ⇒t=139° Hence t=139°
Jeffrey Jordon
Expert2021-12-02Added 2575 answers
Maximum Value−Minimum Value=x23
Maξμm Value−M∈iμm Value=3{x2}
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