Circle has the equation x^2+y^2-6x+10y-15=0, how do you graph the circle using the center (h,k) radius r?

ddioddefn5cw

ddioddefn5cw

Answered question

2023-02-22

Circle has the equation x 2 + y 2 - 6 x + 10 y - 15 = 0 , how do you graph the circle using the center (h,k) radius r?

Answer & Explanation

Helen Merritt

Helen Merritt

Beginner2023-02-23Added 3 answers

A two-dimensional number line, such as two perpendicular number lines oraxes, can be thought of as a coordinate system. This coordinate system is typical: The x-axis and y-axis are the names of the horizontal and vertical axes, respectively. The origin is the point at which all lines in a coordinate system intersect.
Riley Cisneros

Riley Cisneros

Beginner2023-02-24Added 7 answers

The standard equation of a circle, center C = ( h , k ) and radius = r is
( x - h ) 2 + ( y - k ) 2 = r 2
Complete the square to change the given equation to standard form.
x 2 + y 2 - 6 x + 10 y - 15 = 0
x 2 - 6 x + y 2 + 10 y = 15
x 2 - 6 x + 9 + y 2 + 10 y + 25 = 15 + 9 + 25
( x - 3 ) 2 + ( y + 5 ) 2 = 49 = 7 2
The center is = ( 3 , - 5 ) and the radius is = 7
The graph is as follows :
graph{x^2+y^2-6x+10y-15=0 [-14.8, 17.23, -12.3, 3.72]}

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