Tanya Love

2023-02-22

In the given figure 'O' is the centre of the circle and AB is tangent at B. If AB = 15 cm and AC = 7.5 cm. Calculate the diameter of the circle (in cm)

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Angle OBA = 90 degrees
(By theorem, the radius across the point of contact is perpendicular to the tangent at any point on a circle.)
Pythagoras theorem in right angled ABO
$⇒O{B}^{2}=O{A}^{2}-A{B}^{2}\phantom{\rule{0ex}{0ex}}{r}^{2}=\left(r+7.5{\right)}^{2}-{15}^{2}\phantom{\rule{0ex}{0ex}}r2={r}^{2}+56.25+15r-225\phantom{\rule{0ex}{0ex}}15r=168.75\phantom{\rule{0ex}{0ex}}r=11.25cm\phantom{\rule{0ex}{0ex}}\therefore Diameter=2r=2×11.25=22.5cm$

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