Which strategy should I use? Sometimes I'll use U=1/2kx^2 when I should use F=−kx and vice versa.

mundocromadomg

mundocromadomg

Answered question

2022-09-25

Which strategy should I use to approach a problem? Sometimes I'll use U = 1 / 2 k x 2 when I should use F = k x and vice versa. What are clues in a problem that would let me identify the correct approach to a given problem? And shouldn't both approaches give me the same answer in any scenario?

Answer & Explanation

Mario Dorsey

Mario Dorsey

Beginner2022-09-26Added 12 answers

Obviously both are equivalent, in terms of applicability (you get the second directly by taking the gradient of the first).
My "rule of thumb" is that for simple exercices,
the energy view is more suited for initial/final state problems (like, "find the end velocity of mass" or "find the maximal stretch of the spring") because you don't have to integrate the force,
the force view is more suited for trajectory problems (like "find the position of the mass as a function of time") because you don't have to derivate the energy.
Of course that's only a way to choose one way to start solving a given problem; most of the time both are perfectly usable.
When going to more complicated problems however this "rule" is not necessary true ; in any case you should choose the one that gives you as little unnecessary information as possible - while still answering the question.
ye1neh4

ye1neh4

Beginner2022-09-27Added 2 answers

Force is just minus gradient of U. Gradient is just (spatial) derivative.
F = d d x k x 2 2 = 2 x k 2 = k x
So, if your task has "differential" nature, it will probably suitable for force method. And if your task has "integral" nature, then it will probably suitable for potential method.

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