To throw a discus, the thrower holds it with a fully outstretched arm.

Lennie Davis

Lennie Davis

Answered question

2021-12-22

To throw a discus, the thrower holds it with a fully outstretched arm. Starting from rest, he begins to turn with a constant angular acceleration, releasing the discuss after making one complete revolution. The diameter of the circle in which the discus moves is about 1.8 m. If the thrower takes 1.0 s to complete one revolution, starting from rest, what will be the speed of the discus at release?

Answer & Explanation

Jimmy Macias

Jimmy Macias

Beginner2021-12-23Added 30 answers

We have 2r=1.8 mt=1 s 
The discus starts to move from the state of rest v0=0rads 
And we have the expression: 
θ=ω0t+12+12αt2 
θ=0+12αt2 
Thrower performs a circular motion during movement, so θ=2π 
α=2θt2 
α=22π1s2 
α=4πrads2 
α=43.14rads2 
α=12.56rads2 
The speed of the discus at release is: 
v=rω  
v=11.3ms

Do you have a similar question?

Recalculate according to your conditions!

New Questions in Force, Motion and Energy

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?