How much energy is required to ionise a H atom if the electron occupies n = 5 orbit?

Phoebe Ware

Phoebe Ware

Answered question

2023-02-17

How to find a unit vector normal to the surface x 3 + y 3 + 3 x y z = 3 ay the point(1,2,-1)?

Answer & Explanation

Roy Mcclain

Roy Mcclain

Beginner2023-02-18Added 9 answers

The following is an expression for energy:
E 0 = ( 2.18 × 10 18 ) Z 2 n 2
Where,
Z = atomic number of the atom
n = principal quantum number
For ionization from n 1 = 5   t o   n 2 = ,
E = E E 5 = [ ( 2.18 × 10 18 J ) ( 1 ) 2 ( ) 2 ( 2.18 × 10 18 J ) ( 1 ) 2 ( 5 ) 2 ] = ( 2.18 × 10 18 J ) ( 1 ( 5 ) 2 ) ( S i n c e   1 = 0 ) = 0.0872 × 10 18 J E = 8.72 × 10 20 J
Therefore, the energy required for ionization from n = 5 to n = Energy required for n1 = 1 to n = , is 8.72 × 10 20 J.
E = E E 1 = [ ( 2.18 × 10 18 ) ( 1 ) 2 ( ) ( 2.18 × 10 18 ) ( 1 ) 2 ( 1 ) 2 ] = ( 2.18 × 10 18 ) = 2.18 × 10 18 J
Thus, less energy is required to ionize an electron in the 5th orbital of hydrogen atom as compared to that in the ground state.


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