A wheel rotates with a constant angular acceleration of 3.6 r a d / s 2 . If angular velocity of the wheel is 4.0 rad/s at time t 0 = 0, what angle does the wheel rotate in 1 s? What will be its angular velocity at t=1 s?A) θ = 5.8 r a d , ω = 0.4 r a d / sB) θ = 2.2 r a d , ω = 0.4 r a d / sC) θ = 5.8 r a d , ω = 7.6 r a d / sD) θ = 2.2 r a d , ω = 7.6 r a d / s

Question

A wheel rotates with a constant angular acceleration of   3.6  r  a  d      /        s    2  . If angular velocity of the wheel is 4.0 rad/s at time       t    0    =  0, what angle does the wheel rotate in 1 s? What will be its angular velocity at t=1 s?A)   θ  =  5.8  r  a  d  ,  ω  =  0.4  r  a  d      /    sB)   θ  =  2.2  r  a  d  ,  ω  =  0.4  r  a  d      /    sC)   θ  =  5.8  r  a  d  ,  ω  =  7.6  r  a  d      /    sD)  θ  =  2.2  r  a  d  ,  ω  =  7.6  r  a  d      /    s

Ashly Mckinney · Accepted Answer

The correct answer is C:   θ  =  5.8  r  a  d  ,  ω  =  7.6  r  a  d      /    sGiven,Angular acceleration   α  =  3.6  r  a  d      /        s    2  Angular velocity of wheel at       t    O    =  O  ,      ω    O    =  4.0  r  a  d      /    sAngle rotated in 1 second from eq.   θ  =      ω    O    t  +      1    2    α      t    2    θ  =  4  (  r  a  d      /    s  )  ×  1  (  s  )  +      1    2    ×  (  3.6  r  a  d      /        s    2    )  ×  1  ×  (  s      )    2    θ  =  5.8 radFrom eqn.   ω  =      ω    O    +  α  t, angular velocity at t=1 s  ω  =  4  (  r  a  d      /    s  )  +  3.6  (  r  a  d      /        s    2    )  ×  1  (  s  )  ω  =  7.6  r  a  d      /    s

A wheel rotates with a constant angular acceleration of 3.6 rad/s^2.

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