The small piston of a hydraulic lift has an area of 0.20m^2.

emnehefteye4

emnehefteye4

Answered question

2022-12-26

The small piston of a hydraulic lift has an area of 0.20m2. A car weighing 1.20×104N sits on a rack mounted on the large piston. The large piston has an area of 0.90m2. How much force must be applied to the small piston in order to support the car?

Answer & Explanation

Oscar Black

Oscar Black

Beginner2022-12-27Added 7 answers

Step 1: Given:
Weight of the car is W=1.20×104N
Area of small piston A1=0.20m2
Area of a large piston is A2=0.90m2
Let force applied on small piston be F.
Step 2: Finding force (F)-
Pascal's law states that the intensity of pressure (P) remains constant.
, P=WA2=FA1=1.20×1040.90=F0.20F=1.20×104×0.200.90=2.7×103N
Therefore, the value of force is 2.7××103N

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