IndologietVy

2022-11-25

How do you find the midpoint of (-2, 2), (4, 10)?

Teagan Gamble

Expert

Step 1
The midpoint of $A\left({x}_{1},{y}_{1}\right)\phantom{\rule{1ex}{0ex}}\text{and}\phantom{\rule{1ex}{0ex}}B\left({x}_{2},{y}_{2}\right)$ is
$M\left(\frac{{x}_{1}+{x}_{2}}{2},\frac{{y}_{1}+{y}_{2}}{2}\right)$
We have, $A\left(-2,2\right)\phantom{\rule{1ex}{0ex}}\text{and}\phantom{\rule{1ex}{0ex}}B\left(4,10\right)$
So,
Midpoint of $\overline{AB}=M\left(\frac{-2+4}{2},\frac{2+10}{2}\right)$
i.e. Midpoint of $\overline{AB}=M\left(1,6\right)$

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