Find the solutions of equation over the interval [0, 2 pi). cos(x)+sqrt3=5 sqrt3

Vijay Biradar

Vijay Biradar

Answered question

2022-09-15

Answer & Explanation

user_27qwe

user_27qwe

Skilled2023-06-01Added 375 answers

To solve the equation:
8cos(x)+3=53
We can begin by isolating the cosine term on one side of the equation:
8cos(x)=533
8cos(x)=43
Next, we divide both sides by 8 to solve for cos(x):
cos(x)=438
cos(x)=32
Now, we need to find the values of x in the interval [0, 2\pi) that satisfy this equation.
In the interval [0,2π), the values of x for which cos(x)=32 are π6 and 11π6. These correspond to the angles at which the cosine function has a value of 32.
Thus, the solution to the equation over the interval [0,2π) is:
x=π6 and x=11π6

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