PQ and RS are two equal and parallel line segments. Any point M not lying on PQ or RS is joined to Q and S and lines through P parallel to QM and through R parallel to SM meet at N. Prove that line segments MN and PQ are equal and parallel to each other.

Aron Pierce

Aron Pierce

Answered question

2022-12-22

PQ and RS are two equal and parallel line segments. Any point M not lying on PQ or RS is joined to Q and S and lines through P parallel to QM and through R parallel to SM meet at N. Prove that line segments MN and PQ are equal and parallel to each other.

Answer & Explanation

Josselyncx6

Josselyncx6

Beginner2022-12-23Added 10 answers


Since, PQ=RS and PQ∥RS, hence, PQRS is a parallelogram.
Thus, PR∥QS and PR=QS
Now, ∠RPQ+∠PQS=180∘
⇒∠RPQ+∠PQM+∠MQS=180∘ ...(i)
Also, PN∥QM
⇒∠NPQ+∠PMQ=180∘
⇒∠NPR+∠RPQ+∠PQM=180∘...(ii)
From (i) and (ii),
⇒∠NPR=∠MQS
Similarly , we can prove that ∠NRP=∠MSQ
So, in ΔNPR and ΔMQS,
∠NPR=∠MQS
∠NRP=∠MSQ
PR=QS
∴ΔNPR≅ΔMQS by ASA rule.
⇒PN=MQ,NR=MS (By CPCT)
Hence, PQMN and RSMN are both the parallelograms with common side MN
Therefore, MN∥PQ

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