Contain linear equations with constants in denominators. Solve each equation 5+x−23=x+38

BenoguigoliB

BenoguigoliB

Answered

2021-02-12

Contain linear equations with constants in denominators. Solve each equation
5+x23=x+38

Answer & Explanation

Mitchel Aguirre

Mitchel Aguirre

Expert

2021-02-13Added 94 answers

5+x23=x+38
5+x23=x+38
Multiply both sides by 3×8=24
Note that 24 is a product of 3 and 8, Which are the denominators of the fractions in LHS and RHS
24×5+24×x23=24×x+38
120+8(x2)=3(x+3)
120+8x16=3x+9
8x+104=3x+9
Subtract 3x from both sides, To get
5x+104=9
Subtract 104 from both sides, To get
5x=9104
bz=95
Divide both sides by 5, To get
x=955=19
We get the finally result
x=19

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