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Laplace transform

2022-02-05

nick1337

Expert2022-03-08Added 573 answers

We know that:$L\left(u\left(t\right)\right)=\frac{1}{s}$By t shifting theorem$L\left(u(t-2)\right)={e}^{-2s}L\left(u\left(t\right)\right)=\frac{{e}^{-2s}}{s}$Answer would be$\left(d\right)\frac{{e}^{-2s}}{s}$

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