Solve the equation separable, linear, bernoulli, or homogenous1.dydx=x4+4xy22x3+x2y+y32.(e−ycos(x))y′=x4+6x2y33.y′=y+yx3x+x2cos(x2y2)
Quentin Johnson
Answered
2022-01-22
Solve the equation separable, linear, bernoulli, or homogenous
Answer & Explanation
Hector Roberts
Expert
2022-01-22Added 31 answers
Separable equation:
A first order differential equation y’=f(x,y) is called a separable equation if the function f(x,y) can be factored into the product of two functions of x and y
where and are continuous functions.
Linear differential equation:
A first order differential equation is linear when it can be written as:
Where P(x) and Q(x) are functions of x.
Bernoulli differential equation:
A first order Bernoulli differential equation can be written as:
Where P(x) and Q(x) are functions of x.
Bernoulli differential equation:
A first order Bernoulli differential equation can be written as:
Where P(x) and Q(x) are functions of x.
Homogeneous differential equation:
A first order homogeneous differential equation can be written as:
All three equations are written in the table :
\[\begin{array}{|c|c|}\hline Equation & Separable & Linear & Bernoilli & Homogeneous\ \hline \frac{dy}{dx}=\frac{x^4+4xy^2}{2x^3+x^2y+y^3} & no & no & no & no\\hline (e^{-y}\cos(x))y=x^4+6x^2y^3