In the following problems, obtain the differential equations of the

Priscilla Johnston

Priscilla Johnston

Answered question

2022-01-15

In the following problems, obtain the differential equations of the given families of curves whose properties are indicated
Parabolas with vertex on the y-axis, with axis parallel to the x-axis, and with distance from the focus to vertex fixed at a.

Answer & Explanation

Esta Hurtado

Esta Hurtado

Beginner2022-01-16Added 39 answers

The parabola will be of type Y2=4AX, thus the equation of the parabola is
(yh)2=4a(x0) where a is the distance between focus and vertex.
Differentiate (yh)2=4a(x0) with respect to x to obtain equation 1
(yh)2=4a(x0)
2(yh)dydx=4a
2(yh)y=4a (1)
Differentiate 2(yh)y=4a with respect to x to obtain equation 2.
2(yh)y=4a
2(yh)y+2(y)2=0
y(yh)+(y)2=0 (2)
Solve equation 2 and obtain the value of h in terms of y' and y''.
y(yh)+(y)2=0
yyhy+(y)2=0hy=(y)2yy
h=((y)2+yy)y
h=((y)2+yy)y
Substitute the value of h in equation 1 and obtain the value of a.
2(yh)y=4a
2(y(((y)2+yy}{y}y=4a
2(yy(y)2+yyy)y=4a
2(2yy(y)2y)y=4a
2y(y)y(y)3
intacte87

intacte87

Beginner2022-01-17Added 42 answers

The equation of the circle will be of the form
x2+y2=16
The differential equation in this case will be
2x+2yy=0
2yy=2x
dydx=xy
The parabola with the vertex on the y-axis will be of the form
(yh)2=4a(xk)
Hence the equation in this case will be of the form
y=2ay
Note - Post any doubts/queries in comments section.
alenahelenash

alenahelenash

Expert2022-01-24Added 556 answers

Two way parabola possible for given questionEquation of parabolaY2=4AX(yh)2=4a(x0)(yh)2=4axi)Differentiate equation i)2(yh)dy/dx=4a2(yh)y=4aii)Again differentiate2y(yh)+(y)2=0Yyyh+y2=0h=[y+y2/y]put value of h in ii)2(yyy2/y)y=4a[1/2y2y/y=a]Put values of a and h in eq i)(yyy2/y)2=2y2yx/yy2=2yyxy2=2dy/dxd2y/dx2xy2+2dy/dxd2y/dx2x=0

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