Solve the differential equations: (1+x2+y2+x2y2)dy=y2dx

Simplifying
${\displaystyle (1+x^2+y^2+x^2{y}^2)\cdot dy=y^{2}dx}$
Reorder the terms:
${\displaystyle (1+x^2+x^2{y}^2+y^2)\cdot dy=y^{2}dx}$
Reorder the terms for easier multiplication:
${\displaystyle dy(1+x^2+x^2{y}^2+y^2)=y^{2}dx}$
${\displaystyle (1\cdot dy+x^2\cdot dy+x^2{y}^2\cdot dy+y^2\cdot dy)=y^{2}dx}$
Reorder the terms:
${\displaystyle ({dx}^{2}y+{dx}^2{y}^3+1dy+{dy}^3)=y^{2}dx}$
${\displaystyle ({dx}^{2}y+{dx}^2{y}^3+1dy+{dy}^3)=y^{2}dx}$
Solving
${\displaystyle {dx}^{2}y+{dx}^2{y}^3+1dy+{dy}^3=dx{y}^2}$
Solving for variable d.
Move all terms containing d to the left, all other terms to the right.
Add ${\displaystyle -1left.dxright.y^2}$ to each side of the equation.
${\displaystyle {dx}^{2}y+{dx}^2{y}^3+1dy+-1dx{y}^2+{dy}^3=dx{y}^2+-1dx{y}^2}$
Reorder the terms: