xcos2y dx+tan⁡y dy=0

Patricia Crane

Patricia Crane

Answered

2021-12-28

xcos2y dx+tany dy=0

Answer & Explanation

kalfswors0m

kalfswors0m

Expert

2021-12-29Added 24 answers

xcos2y dx+tany dy=0
From variable seperation method
xcos2y dx=tany dy
xdx=tanycos2ydy
xdx=tanysec2y dy
Let tany=t
x22=t dt sec2y dy=dt
c+x22=t22
x22+c=tan2y2
tan2y2=x22+c
Maricela Alarcon

Maricela Alarcon

Expert

2021-12-30Added 28 answers

xcos2y dx+tany dy=0
tan y dy=xcos2y dx
tanysec2y dy=x dx
tanysec2y dy=x dx
12tan2y=12x2+c0
x2+tan2y=C
Vasquez

Vasquez

Expert

2022-01-09Added 457 answers

xcos2ydx+tanydy=0xdx+tanysec2ydy=0Let tany=tsec2y dy=dtxdx+tdt=c1x22+t22=2c1x2+tan2y=2c1x2+sec2y=2c1+1 put (2c1+1)=cx2+sec2y=c

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