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xcos2ydx+tanydy=0⇒xdx+tanysec2ydy=0Let tany=t⇒sec2y dy=dt∫xdx+∫tdt=c1⇒x22+t22=2c1x2+tan2y=2c1x2+sec2y=2c1+1 put (2c1+1)=c⇒x2+sec2y=c
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