Find Answers
Get Study Tools
First order differential equations
Ernstfalld
2021-03-07
brawnyN
Skilled2021-03-08Added 91 answers
xu′(x)=u2−4xu′(x)1u2−4=11u2−4du=1xdxIntegrating on both sides∫1u2−4du=∫1xdxThe partial fraction of the left side 1(u+2)(u−2)=−14(x+2)+14(x−2)−14∫1u+2du+14∫1u−2du=∫1xdx−14ln(u+2)du+14ln(u−2)=ln(x)+C1−ln(u+2)du+ln(u−2)=4ln(x)+4C1ln(u−2u+2)=ln(x4)+C2(u−2u+2)=(x4)+eC2=x4+Cu=−2(C+x4)−C+x4
Jeffrey Jordon
Expert2021-12-25Added 2575 answers
Answer is given below (on video)
Do you have a similar question?
Recalculate according to your conditions!
Ask your question. Get an expert answer.
Let our experts help you. Answer in as fast as 15 minutes.
Didn't find what you were looking for?