Solve differential equation dy/dx−12x3y=x3

$dy/dx=x^3+12x^{3}y$
$dy/dx=x^3(1+12y)$
$dy/((1+12y))=x^{3}dx$
Taking Integration on both sides, we get
$\int dy/(1+12y)=\int x^{3}dx$
Using u− substitution rule
Let $u=1+12y$
$du=12dy$
$dy=1/12du$
Substituting the values above
$\int dy/(1+12y)=\int x^{3}dx$
$1/12\int (du)/u=x^4/4+C$
Integrating
$1/12u=x^4/4+C$
$1/12\ln (1+12y)=x^4/4+C$
Isolating y
$\ln (1+12y)=3x^4+12C$
$\ln (1+12y)=3x^4+C_1$
$1+12y=e^{3x^4+C_1}$
$y=(e^{3x^4+C_1}-1)/12$
$y=(e^{3x^4+C_1})/12-1/12$