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Derivatives

grasaladae5

2021-12-07

Keith Dooley

Beginner2021-12-08Added 14 answers

Step 1 Given, $y=(1+{x}^{2}){e}^{{\mathrm{tan}}^{-1}x}$ Step 2 differentiate w.r.t "x" $\frac{dy}{dx}=(2x){e}^{{\mathrm{tan}}^{-1}x}+(1+{x}^{2}){e}^{{\mathrm{tan}}^{-1}x}(\frac{1}{1+{x}^{2}})$ $\frac{dy}{dx}=2x{e}^{{\mathrm{tan}}^{-1}x}+{e}^{{\mathrm{tan}}^{-1}x}$ $\frac{dy}{dx}=(2x+1){e}^{{\mathrm{tan}}^{-1}x}$

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