Two runners start a race at the same time and finish in a tie. Prove t

vakirnarhh

vakirnarhh

Answered question

2021-11-16

Two runners start a race at the same time and finish in a tie. Prove that at some time during the race they have the same speed. [Hint: Consider f(t)=g(t)h(t) , where and are the position functions of the two runners.

Answer & Explanation

Steacensen69

Steacensen69

Beginner2021-11-17Added 15 answers

Step 1
f(t)=g(t)h(t) - the difference positions of two runners.
g(t)h(t) are continuons and differentiable. So, f(t) is too continuons and differentiable.
We want to show that there was no velocity difference between the runners at some point during the race.

Find the first derivative of the equation f(t)=g(t)h(t).
f(t)=g(t)h(t)
Consider the intreval (t0,t1), where is the start time t0 and the finish time t1.
Is given that runners start a race at same time and finis in a tie.
So, g(t0)=h(t0) and g(t1)=h(t1).
We have: f(t0)=0 and f(t1)=0
We can apply the Rolle's theorem, because we have: f(t0)=f(t1) and f(t) is continuons and differentiable.
So, there exists some cc that such f(c)=0
f(c)=g(c)h(c)=0
g(c)=h(c)
For c=tt(t0,t1)
g(t)=h(t)
Answer
Apply the Rolle's theorem.

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