Twenty volunteers at a cold research institute caught a cold after having been exposed to various cold viruses. Ten of the volunteers were randomly selected to receive tablets containing 1 gram of vitamin C. These tablets were taken four times a day. The control group, consisting of the other 10 volunteers, was given placebo tablets that looked and tasted exactly like the vitamin C ones. This was continued for each volunteer until a doctor, who did not know whether one volunteer was receiving vitamin C or the placebo, decided that the volunteer was no longer suffering from the cold. The length of time the cold lasted was then recorded. At the end of the experiment, the following data resulted: The average length of cold for the n_1 = 10 people treated with vitamin C is with a standard devi

Tyson Atkins

Tyson Atkins

Answered question

2022-10-29

Twenty volunteers at a cold research institute caught a cold after having been exposed to various cold viruses. Ten of the volunteers were randomly selected to receive tablets containing 1 gram of vitamin C. These tablets were taken four times a day. The control group, consisting of the other 10 volunteers, was given placebo tablets that looked and tasted exactly like the vitamin C ones. This was continued for each volunteer until a doctor, who did not know whether one volunteer was receiving vitamin C or the placebo, decided that the volunteer was no longer suffering from the cold. The length of time the cold lasted was then recorded. At the end of the experiment, the following data resulted
:The average length of cold for the n 1 ==10 people treated with vitamin C is with a standard deviation of s 1 ==0.76
The average length of cold for the n 2 ==10 people receiving the placebo is with a standard deviation of s 2 =0.85
Determine the value of the pooled standard deviation . Round your answer three decimal places.

Answer & Explanation

pawia6g

pawia6g

Beginner2022-10-30Added 14 answers

Solution:
From the given information, n1=10, s1=0.76, n2=10 and s2=0.85.
The pooled standard deviation is obtained by using the following formula:
S p o o l e d = ( n 1 1 ) s 1 2 + ( n 2 1 ) s 2 2 n 1 + n 2 2

Then,
S p o o l e d = ( n 1 1 ) s 1 2 + ( n 2 1 ) s 2 2 n 1 + n 2 2 = ( 10 1 ) 0.76 2 + ( 10 1 ) 0.85 2 10 + 10 2 = 11.7009 18 = 0.806
Thus, the value of the pooled standard deviation is 0.806.

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