The concentration of alcohol in a person’s bloodstream is measurable. Suppose that the relative risk R of having an accident while driving a car can be modeled by an equation of the form R=e^(kx) where x is the percent of concentration of alcohol in the bloodstream and k is a constant. Using this value of k, what is the relative risk if the concentration is 0.17 percent?

Krish Logan

Krish Logan

Answered question

2022-10-18

The concentration of alcoholin a person's bloodstream is measurable.
Suppose that the relative risk R of having an accident while driving a car can be modeled by an equation of the form R = e k x where x is the percent of concentration of alcohol in the bloodstream and k Is a constant Using this value of k, what is the relative risk if the concentration is 0.17 percent?

Answer & Explanation

blogpolisft

blogpolisft

Beginner2022-10-19Added 10 answers

From part(a), k = ln 1.4 0.03 11.2157
Thus, the equation becomes R = e ln 1.4 0.03 k
Substitute 0.17 to R to obtain:
R = e ln 1.4 0.03 0.17
=6.730678848
6.73
Result
6.73

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